Question 1

A new monocyclic ring is formed. The pi-electron energy of the ring is calculated and found to be the exact same as the pi-electron energy of the corresponding open chain form of the ring with the same number of carbons and double bonds.

Accepted Answer

A)   aromatic
B)   antiaromatic
C)   nonaromaticD) B) and C)
E) A) and B)

Question 2

Which of the following are aromatic?

Accepted Answer

A)   I
B)   II
C)   III
D)   I and II
E)   II and IIIF)  I and IIIG)  none of the aboveH)  all of the aboveI) A) and B)
J) B) and G)

Question 3

Which of the following are aromatic?

Accepted Answer

A)   I
B)   II
C)   III
D)   I and II
E)   II and IIIF)  I and IIIG)  none of the aboveH)  all of the aboveI) A) and G)
J) G) and H) F

Question 4

To be aromatic, a compound must be ___ , ___ , contain alternating double and single bonds and have
A(n)  ___ of electrons.

Accepted Answer

A)   noncyclic, coplanar, even number
B)   cyclic, symmetric, odd number
C)   cyclic, planar, Huckel
D)   cyclic, aliphatic, HuckelE) A) and B)
F) A) and C)

Question 5

What is the correct name for the following?

Accepted Answer

A)   o-bromoaniline
B)   2-bromoaniline
C)   1-amino-2-bromobenzene
D)   all of the aboveE) B) and C)
F) None of the above

Question 6

What is the correct name for the following?

Accepted Answer

A)   o-nitrophenone
B)   p-hydroxynitrobenzene
C)   3-nitroacetophenone
D)   m-nitrophenolE) A) and C)
F) A) and B) D

Question 7

A new monocyclic ring is formed. The pi-electron energy of the ring is calculated and found to be 25 kJ/mole lower than the pi-electron energy of the corresponding open chain form of the ring with the same number of carbons and double bonds.

Accepted Answer

A)   aromatic
B)   antiaromatic
C)   nonaromaticD) All of the above
E) A) and B) A

Question 8

Which of the following represents the two major fragments that are seen when monoalkylbenzenes fragment in a Mass Spectrometer?

Accepted Answer

A)   I and II 
B)   I and III 
C)   I and IV 
D)   II and III 
E)   III and IV F)  II and IVG) C) and F)
H) B) and D)

Question 9

In NMR, aromatic hydogens resonate at ___ ppm while carbons resonate at ___ ppm. In IR spectroscopy, aromatic hydrogens absorb at ___ cm-1.

Accepted Answer

A)   3-4, 100-170, 1450-1600
B)   6-9.5, 100-170, 3030
C)   3-4, 100-170, 2250
D)   6-9.5, 100-170, 1450-1600E) A) and B)
F) A) and C)

Question 10

___ is the general name for all monocyclic structures that contain alternating double and single bonds.

Accepted Answer

A)   Annulenes
B)   Cumulenes
C)   Aromatics
D)   AntiaromaticsE) All of the above
F) A) and B)

Exam 14: Aromatic Compounds

A new monocyclic ring is formed. The pi-electron energy of the ring is calculated and found to be the exact same as the pi-electron energy of the corresponding open chain form of the ring with the same number of carbons and double bonds.

Correct Answer
verified

Which of the following are aromatic?

Correct Answer
verified

Which of the following are aromatic?

Correct Answer
verified
F

To be aromatic, a compound must be _ , _ , contain alternating double and single bonds and have A(n) ___ of electrons.

Correct Answer
verified

What is the correct name for the following?

Correct Answer
verified

What is the correct name for the following?

Correct Answer
verified
D

A new monocyclic ring is formed. The pi-electron energy of the ring is calculated and found to be 25 kJ/mole lower than the pi-electron energy of the corresponding open chain form of the ring with the same number of carbons and double bonds.

Correct Answer
verified
A

Which of the following represents the two major fragments that are seen when monoalkylbenzenes fragment in a Mass Spectrometer?

Correct Answer
verified

In NMR, aromatic hydogens resonate at _ ppm while carbons resonate at _ ppm. In IR spectroscopy, aromatic hydrogens absorb at ___ cm^-1.

Correct Answer
verified

___ is the general name for all monocyclic structures that contain alternating double and single bonds.

Correct Answer
verified

Exam 14: Aromatic Compounds

A new monocyclic ring is formed. The pi-electron energy of the ring is calculated and found to be the exact same as the pi-electron energy of the corresponding open chain form of the ring with the same number of carbons and double bonds.

Correct AnswerverifiedShow Answer

Which of the following are aromatic?

Correct AnswerverifiedShow Answer

Which of the following are aromatic?

Correct AnswerverifiedF

To be aromatic, a compound must be ___ , ___ , contain alternating double and single bonds and have A(n) ___ of electrons.

Correct AnswerverifiedShow Answer

What is the correct name for the following?

Correct AnswerverifiedShow Answer

What is the correct name for the following?

Correct AnswerverifiedD

A new monocyclic ring is formed. The pi-electron energy of the ring is calculated and found to be 25 kJ/mole lower than the pi-electron energy of the corresponding open chain form of the ring with the same number of carbons and double bonds.

Correct AnswerverifiedA

Which of the following represents the two major fragments that are seen when monoalkylbenzenes fragment in a Mass Spectrometer?

Correct AnswerverifiedShow Answer

In NMR, aromatic hydogens resonate at ___ ppm while carbons resonate at ___ ppm. In IR spectroscopy, aromatic hydrogens absorb at ___ cm-1.

Correct AnswerverifiedShow Answer

___ is the general name for all monocyclic structures that contain alternating double and single bonds.

Correct AnswerverifiedShow Answer

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified
F

To be aromatic, a compound must be _ , _ , contain alternating double and single bonds and have A(n) ___ of electrons.

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified
D

Correct Answer
verified
A

Correct Answer
verified

In NMR, aromatic hydogens resonate at _ ppm while carbons resonate at _ ppm. In IR spectroscopy, aromatic hydrogens absorb at ___ cm^-1.

Correct Answer
verified

Correct Answer
verified